2x^2+15x-1100=0

Solution for 2x^2+15x-1100=0 equation:

2x^2+15x-1100=0

a = 2; b = 15; c = -1100;
Δ = b2-4ac
Δ = 152-4·2·(-1100)
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9025}=95$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-95}{2*2}=\frac{-110}{4}
=-27+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+95}{2*2}=\frac{80}{4}
=20
$